Can some one plz awnser all 3 of them? Test tomorrow 2 o. Exam 1 NGEN 3322 Fall
ID: 3280232 • Letter: C
Question
Can some one plz awnser all 3 of them? Test tomorrow 2 o. Exam 1 NGEN 3322 Fall 2016 September 29, 2016 Write procedure, units and assumptions if needed Problem 1 Initial pressure is above the bubble point pressure of a undersaturated oil (black oill in the reservcir. As production begins, reservoir pressure decreases, how do the following fluid properties change? Select "increases", "decreases", or, "remain constant. Fill in the blanks, Coefficient of oil isothermal compressibility..inca&. Oil formation volume factor.t Solution gas oil ratio. Total formation volume factor.s Problem 2 Calculate (1) the molecular weight, (2) specific gravity, (3) compressibility factor. component methane ethane propane Hydrogen sulfide Ca Mole fraction 0.94 0.02 0.01 0.03 Problem 3 Calculate the formation volume factor and viscosity of the gas of problem 2 at 4000 psia and 200F. Pb 300o psja.Explanation / Answer
1.
the coefficient of oil isothermal compressibility: Increases
The oil compressibility is defined as the relative change in oil volume per unit change in pressure. If Pressure decreases then volume increases. so that, the coefficient of oil isothermal compressibility is Increases
Oil Viscosity: Increases
The viscosity decreases with increasing temperature and pressure (up to the bubble point).So Here, The Viscosity is increased by decreasing pressure.
Oil formation volume factor: decreases
Oil formation volume factor is influenced by two main factors. The dominant factor is solution gas. As pressure decreases, the amount of solution gas that the oil can dissolve decreases such that the oil swells, and so the formation volume factor Decreases.
Solution gas oil ratio: decreases
The solution gas-oil ratio decreases with pressure until the bubble point pressure is reached, after that it is a constant, and the oil is said to be undersaturated.
Total formation volume factor: Remains constant.
2.
Molecular weight:
M = summation of {(mole fraction component)(Molecular weight of component)}
= 0.94(16.04 g/mol) + 0.02(30.07 g/mol)+0.01(44.1 g/mol)+0.03(34.08 g/mol)
= 17.1424 g/mol.
Specific Gravity = (Molecular weight of gas) /( Molecular weight of dry air = 28.96)
= (17.1424)/(28.96)
= 0.59
Compressibility factor =