Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Newton\'s Laws-4 1. Is it possible for a particle to move at a constant speed wh

ID: 3280302 • Letter: N

Question

Newton's Laws-4 1. Is it possible for a particle to move at a constant speed while accelerating? Explain. 2. What do we mean by a uniform eircular motion? Explain 3. A simple pendulum consists of a light wire of length / connected to a bob of mass m. If the bob Explain. is released from rest, as shown, is the motion of the bob uniform? Draw the FBD for the bob of mass m-2.0 kg in problem 3 when it is at the bottom of its path. If-1.0 m and the bob's speed v- 5.0 m/s, find the tension in the string at that instant. Will the tension change as the mass moves on? Does the tension increase, decrease or stay the same? Explain. 4. 5. If the string of a pendulum in problem 3 breaks when the bob is at the bottom of its path, in what direction will it travel? Explain. 6. Consider a conical pendulum discussed in class. Draw the FBD for mass m. Find the speed of a particle of mass m as it executes a uniform circular motion. Your answer should be expressed in terms of the length I of the pendulum and angle with the vertical. a. b. c. What is the tension in the string? 7. An experimental airplane flies at 285 m/s Gust shy of a speed of sound in air!). A pilot navigates the plane in a vertical cirit of ramus r= 3.0 km, as shown. Draw the FBD for a pilot at the bottom, top, and a point A of the path shown. a. b. If the pilot's mass is m = 75 kg, find the apparent weight of the pilot at the top, bottom, and the point A of the plane's path

Explanation / Answer

1) Yes it is possible. Uniform circular motion is an example. The object moves with constant speed but there is acceleration also which is towards the center.

2) Uniform circular motion is a motion of an object in a circle with constant speed.

3)Non uniform motion because speed at bottom most point is more than speed at extreme points.

4) T points upward, mg points downward.

T - mg = mv^2/L

T = mg + mv^2/L = 2*9.8 + 2*5^2 /1

=69.6 N answer

Tension will decrease.