Masterin ysics: Ch 24 HW le Chrome Secure | https://session.masteringphysics.com
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Question
Masterin ysics: Ch 24 HW le Chrome Secure | https://session.masteringphysics.com/myct/itemView?assignmentProblemID-83462763 Resources previous | 19 of 25 | next » Ch 24 HWExercise 24.28 Exercise 24.28 Part A For the capacitor network shown in (Figure 1), the potential difference across ab is 53 V Find the total charge stored in this network Express your answer with the appropriate units. Q= 3.5, Submit My Answers Give Up Correct Figure 1 of 1 Part B Find the charge on the 150 nF capacitor Express your answer with the appropriate units. Q1 : 3.5 150 nF 120 nF Submit My Answers Give Up Correct Part C Find the charge on the 120 nF capacitor Express your answer with the appropriate units. 8:17 PM 1.nil 4: 10/10/2017Explanation / Answer
Here ,
V = 53 V
a) as the capacitors are in series
1/Ceq = 1/120 + 1/150
Ceq = 66.7 nF
charge on 120 nF and 150 nF = 66.7 * 53 nC
charge on 120 nF and 150 nF = 3533 nC
charge on 120 nF and 150 nF = 3.53 uC
b)
total energy stored = 0.50 * Ceq * V^2
total energy stored = 0.50 * 66.7 * 10^-9 * 53^2
total energy stored = 9.37 *10^-5 J
c)
Now, for the energy stored in 120 nF
energy stored in 120 nF = 0.50 * (3.53 *10^-6)^2/(120 *10^-9)
energy stored in 120 nF = 5.19 *10^-5 J
energy stored in 150 nF = 9.37 *10^-5 - 5.19 *10^-5
energy stored in 150 nF = 4.18 *10^-5 J
d)
potential across 150 nF = 3.53 *10^-6/(150 *10^-9)
potential across 150 nF = 23.5 V
potential across 120 V = 53 - 23.5
potential across 120 nF = 29.5 V