Please explain your answer. Solution ?0->8 x/(x^3 + 1) dx. Use comparison theore
ID: 3283929 • Letter: P
Question
Please explain your answer.Explanation / Answer
?0->8 x/(x^3 + 1) dx. Use comparison theorem to determine whether the integral is convergent of divergent. 2. Relevant equations None. 3. The attempt at a solution ?0->8 x/(x^3 + 1) dx = ?0->8 x/(x^3) dx = ?0->8 1/(x^2) dx From my class I learned that ?1->8 1/(x^2) dx , is convergent But now that the interval begins from 0 to infinity ?0->8 1/(x^2) dx is divergent! Although my professor, and as well as the back of the book, tells me that ?0->8 x/(x^3+1) dx is convergent. This must mean that I did something wrong... what would that be?