In part c) the bottom right should be -2r^2 * sin(2 * theta) Let x = f(r) be the
ID: 3284964 • Letter: I
Question
In part c) the bottom right should be -2r^2 * sin(2 * theta)
Let x = f(r) be the polar coordinate map of the previous exercise, and let u = g(x) be the map Determine dgx at an arbitrary point x = (x,y)then use the coordinate change x = f(r) to express the derivative in terms of r = (r, theta ): dgf(r).Compute the components of the composite map h = g o f. That is, determine u and v in terms of r and theta ; u = h(r) = g(f(r)). Verify that and also verify that dhr = dgf(r) dfr. (This is another instance of the chain rule.)Explanation / Answer
could you please post the previous exercise as mentioned in the above question.