Question
Please show work
Suppose that an airline assigns passengers to one of three boarding groups. The first group to board is called group A. The airline has determined that, once the call to board group A has been given, the amount of time it takes a passenger in this group to board the aircraft is uniformly distributed between 139 s and 290 s. What is the mean of this distribution? Round your answer to the nearest tenth of a second, mean =. S What is the median of this distribution? Round your answer to the nearest tenth of a second. median = s What is the standard deviation of this distribution? Round your answer to the nearest tenth of a second. standard deviation = s
Explanation / Answer
This is a uniform distribution with the given params of a and b as 139 and 290 seconds.
The mean of this uniform dist is given by:
b-a/2 = 290-139 / 2 = 151/2 = 75.5 seconds
The median of this distribution will be equal to mean = 75.5 seconds
The stdev of this distribution is given by (b-a)^2/12 = (290-139)^2/12 =1900.1 seconds