Refer to the following distribution of commissions for questions 1-5 What is the
ID: 3300522 • Letter: R
Question
Refer to the following distribution of commissions for questions 1-5 What is the class width? 200 800 1800 2200 What is the relative frequency for salespeople that earn from $1, 600 up to 1, 800? 24 0.24 20 0.20 What is the cumulative frequency for salespeople that earn from $1, 400 up to $1600? 0.333 0.667 0.692 0.892 What is the cumulative frequency for salespeople that earn from $2000 up to 2200? 0.333 0.667 0.692 1.000 How many classes should this data set have according to the 2^k graterthanorequalto n rule? 5 6 7 8Explanation / Answer
First we complete the given table.
Formula for relative frequency is Relative Frequency = class frequency/sum of frequencies
Sum of all frequencies =N=3+7+11+22+40+24+9+4=120
Monthly Commissions($)
1) Class width is the difference between two consecutive lower class limits or two consecutive class boundries
class width=800-600=200
answer is A
2) Relative frequncy for the salespeople that earns from $1600 up to $1800 is calculated as
Relative frequency=frequency of class $1600 up yo $1800/sum of all frequency
=24/120
= 0.20
answer is D
3) Cumulative frequncy for the salespeople that earns from $1400 up to $1600 is calculated as
Cumulative frequency= 83/120 = 0.6916 =0.692
answer is C
4)Cumulative frequncy for the salespeople that earns from $2000 up to $2200 is calculated as
Cumulative frequency= 120/120 =1
answer is D
5) 2^k>=n rule :
k:number of classes
n:number of observations=120
We have to find k such that 2^k>=120 ,therefore 2^7=128 which is >=120.
So, the possible number of classes is 7
answer is C
Monthly Commissions($)
Class Frequencies Relative Frequencies Cumulative frequencies 600 up to 800 3 3/120=0.025 3 800 up to 1000 7 7/120=0.0583 3+7=10 1000 up to 1200 11 11/120=0.0916 11+10=21 1200 up to 1400 22 22/120=0.1833 22+21=43 1400 up to 1600 40 40/120=0.3333 40+43=83 1600 up to 1800 24 24/120=0.2 24+83107 1800 up to 2000 9 9/120=0.075 9+107=116 2000 up to 2200 4 4/120=0.0333 4+116=120=N