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An ANOVA test can be done to compare if the average numbers of dinners sold by t

ID: 3305227 • Letter: A

Question

An ANOVA test can be done to compare if the average numbers of dinners sold by three restaurants are identical or not with the level of significance is 0.05. Alternatevly, I decided to do 3 all possible two-sample tests for the hypothesis testing of: H0: h1 = h2 = h3 vs. h1: Not all of the mean values are equal. The, what should be the true level of significance (or Type 1 error) of the hypothesis test? (choose a closet one)

A.) 15%

B.) 25%

C.) 19%

D.) 75%

E.) 81%

SF-Susi    SF-Taco       SF-Pizza

13                    10                   18

12                     12                   16

14                     13                    17

12                     11                     17

                                                  17

Explanation / Answer

here as level of significance =0.05

therefore probability of type 1 error =P(at least one test shows signfiicance) =1-P( none of 3 shows significance)

=1-(!-0.95)3 =~0.15

hence option A is correct