Math-11-85369-FA17 Elementary Statistics Carter Homework: Section 3.3 Homework S

Question

Math-11-85369-FA17 Elementary Statistics Carter Homework: Section 3.3 Homework Score: 0 25 of 1 pt 10 of 10(10 complete) HW Score: 45 83%,458 of 10 pt 3.3.24 The table below shows the resuis of a survey that asked 1069 adults from a certaih country i bhey wouid support a change in thee country's fag A person is selected at random Complete parts (a) through (d) SupportOpposeUnsue 330 308 639 Total 501 568 1069 Males 6 30 36 Propposed the change or is eme) Round to the nearest thousandth as needed) b) Find the probably hat the person supports the change or is male change or s eme)0840 HON INS F11 DEL

Explanation / Answer

We have,

P(A or B) = P(A) + P(B) - P(A and B)

b) P(supports the change or is male) = P(supports the change) + P(male) - P(supports the change and is male)

                                                         = 395/1069 + 501/1069 - 165/1069

                                                         = (395+501-165) / 1069

                                                         = 731/1069 = 0.6838

     

c) We have

P(Ac) = 1 - P(A)

P(not unsure) = 1 - P(unsure)

= 1 - 36/1069 = (1069 - 36) / 1069 = 1033/1069

no. of (not unsure and female) = 568 - 30 = 538

P(not unsure or female) = P(not unsure) + P(female) - P((not unsure and female) )

   = 1033/1069 + 568/1069 - 538/1069

    = (1033+568-538) / 1069

    = 1063/1069 = 0.9944

d) the events "being male" and "support" are not mutually exclusive because in the intersection of male and support, there are 165 peoples.

• P(supports the change or is male) = 0.6838

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