Could you please help me solve Problem F - please see the attached files. Please

Question

Could you please help me solve Problem F - please see the attached files. Please help to do it step-by-step with all the workings and solutions. Thank you very much!

Problem F A local university wants to estimate the average time/week spent on computer laboratory terminals by each student. Data was collected for a sample of 81 students. The sample mean is 9 hours and standard deviation is 1.2 hours. 15. The standard error of the mean is: 16. With 0.95 probability the margin of error is approximatelj 17. The 95% confidence interval is:

Explanation / Answer

Question- F

sample size n = 81

Sample mean xbar = 9 hours

Sample standard deviation s =1.2 hours

15. standard error of the mean (se) = s/ sqrt(n) = 1.2/ sqrt(81) = 0.1333

16. Margin of error for 95% confidence interval = t0.05, 80 * se

here it is sample standard deviation so we will use t. We can use Z values also as sample size is greater than 30

Margin of error = 1.99 * 0.13333 = 0.265

17. 95% confidence interval = xbar +- Margin of error = 9.0 +- 0.265

(8.735, 9.265)

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