Part A-Determine the real world meaning of the coefficients of a parabola Determ

Question

Part A-Determine the real world meaning of the coefficients of a parabola Determine the values of the initial position, initial velocity, and acceleration of the object moving according to the equation below, where r is measured in m and t in s (also shown in (Figure 2)): 10.015.0t49t2 Enter your answer as initial postion in m, initial velocity in m/s, acceleration ineparated by commas. View Available Hint(s) m/s ,,a10,15,-24.01 m,m/ s, SubmitPre X Incorrect: One attempt remaining: Try Again Check your signs.

Explanation / Answer

According to the given problem,

Given the parabola equations,

x = 10.0 + 15.0t - 4.9t2

Derivate the position function with dt to get velocity,

v = dx/dt = 15.0 - 9.8t

Derivate the velocity function with dt to get accelration.

a = dv/dt = -9.8 m/s2

So, The intial values are at t = 0,

x = 10.0 m

v = 15.0 m/s

a = - 9.8 m/s2 [How did you got -24.01 ????]

I hope you understood the problem, If yes rate me! or else comment for a better solution.

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