Please answer the photo which is part B. here was the info for part A. (A certai
ID: 3308459 • Letter: P
Question
Please answer the photo which is part B.
here was the info for part A.
(A certain refrigerator has a COP of 5.00. When the refrigerator is running, its power input is 500 W. A sample of water of mass 200 g and temperature 20.0°C is placed in the freezer compartment. How long does it take to freeze the water to ice at 0°C? Assume all other parts of the refrigerator stay at the same temperature and there is no leakage of energy from the exterior, so the operation of the refrigerator results only in energy being extracted from the water. )
MASTER IT HINTS: GETTING STARTED I IM STUCK Compare the cost to make 40 kg of ice usingt of 6.00. Electricity costs $0.10 per kWh. Using the same assumptions give between the refrigerators to freeze the water? n in the example, find the cost difference cost difference = $ Need Help?Read It Submit Answer Save ProgressPractice Another VersionExplanation / Answer
energy released to freeze,
Q = m C delatT + m Lf
= (40 x 4184 x 20) + (40)(334 x 10^3)
= 16707.2 x 10^3 J
COP = heat aborbed / work supplied.
delta(work supplied) = (16707.2 x 10^3)(1/5 - 1/6)
= 556.91 x 10^3 J
1 kWh = 10^3 x 3600 J
cost = (556.91 x 10^3 / 3600 x 10^3) (0.10)
= 0.0155 dollars