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QUiz 9: MS 1023-001 (Monday November 27h 2017 at 7:30 PM) Name: UTSA ID: YOU MUS

ID: 3311069 • Letter: Q

Question

QUiz 9: MS 1023-001 (Monday November 27h 2017 at 7:30 PM) Name: UTSA ID: YOU MUST SHOW YOUR WORK TO GET ANY CREDIT Problem 1: We would like to compare the mean fill of 32 ounce cans of beer from two adjacent filling machines. Past experience has shown that the population standard deviations of fills for the two machines are known to be ,-004 and ,-0.06 respectively. A sample of 37 cans from machine 1 gave a mean of 17.031 and a sample of 33 cans from machine 2 gave a mean of 17.008 a. State, perform and interpret an appropriate hypothesis test using the 0.05 level of significance. b. Compute the 95% confidence interval for the difference of the two population means

Explanation / Answer

Ans:

standard error for difference of means=sqrt((0.04^2/37)+(0.06^2/33))=0.0123

a)

Test statistic

z=(17.031-17.008)/0.0123=1.86

p-value(2 tailed)=0.0629

As,p-value>0.05,we fail to reject null hypothesis.

There is sufficient evidence to conclude that both means are equal.

b)

95% confidence interval for difference of means

=(17.031-17.008)+/-1.96*0.0123

=0.023+/-0.024

=(-0.001,0.047)