Math 1090-17 Homework: 5.2 Score: 0 of 1 pl 5.2.43 10011011 complete) res y atrn
ID: 3313102 • Letter: M
Question
Math 1090-17 Homework: 5.2 Score: 0 of 1 pl 5.2.43 10011011 complete) res y atrnon hae he t betee 664oeand 75Sichet wat beren age et tan co try the hei 01a a men are nomah den uted w amean of 6 inches and he can tbviawthe table with gtanard scores and peroenses kranormal distribution andard deviat on at 2 5 l ches The outra men ryre nac % The percentage ot menae Igble tor the metary based on height Round ta wo decme places as naeded. 0 Dsta Tabe Ful data se2 Standard Scores and Percentles for a Nomal Distrbubon cumulative values trom the iet % Standard sco% % 5393 09 15 Standard sco" 3.0 0.6203 22 0981.59 668 15 87 -25 05 -2 1.5 84.13 93 32 97 72 99 38 1.5 01841 05 30 85 2.5 500035 Print Dona Enter your aniver in the answer bex and thon dick Check Answer All parts showng ClearExplanation / Answer
Here mean = 69 inches
standard deviation = 2.6 inches
Let say X is the height of a random person
Pr( 66.4 inches< X < 75.5 inches) = Pr (X < 75. 5 inches) - Pr(X < 66.4 inches)
Z2 = (75.5 - 69)/ 2.6 = 2.5
Z1 = (66.4 - 69)/ 2.6 = -1
so Pr(66.4 inches< X < 75.5 inches) = Pr(Z < 2.5) - Pr(Z < -1)
= 0.9938 - 0.1587 = 0.8351
= 83.51%