Please help : obtain the critical value and of the chi-sq for alpha =0.05 . Inte

Question

Please help : obtain the critical value and of the chi-sq for alpha =0.05 . Interpret the results. Based on excell tables, which combination of eye color seems to deviate the most from the expected values under the hypothesis of independence? ( I’m guessing green eyes and black hair because chi-sq value 5.7454 is highest?) Copy of Lab09amabrooks Home Insert Draw Page Layout Formulas Data Review View Help Tell me what File S Cut Calibri Copy . Format Painter Merge&Center; . $.%, Paste Blu- BIU .a.. Number Clipboard Font Alignment Observed values Chi-sac no columns ight tail 0.00735 Always 51 94 68 28 90 47 41 15 113 762 swer each question in the space below the questio 21 Joint and 1. What is your estimate ofthe probability of randomly observing 0008 0067 0091 0089 0037 0.291 00210123 0.118 123 0.062 0.448 26 reen .000 00490910.072 0os0 261 2. State the null hypothesis tested by the calculated Chi-sq in a cor h depe 30 3. Complete the Excel table fore Expected values 530 63.2 32.9 2220 98614020 9750.6 3410 47.5 59$ “7· 295 1990 220 120 2282170 110 762.0 Complete S beoin 7 Total Contingency Table DELL

Explanation / Answer

Answer : Critical value = CHIINV(0.05,8) = 15.507

Here you are right that the green eyes and black hair are the most deviated combination.

Here we can interpret these results that we can reject the null hypothesis and can conclude that eye color is not independent of hair color.

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