Here is the orginal question: Here is the JMP software output if needed: Save Ar
ID: 3321678 • Letter: H
Question
Here is the orginal question:
Here is the JMP software output if needed:
Save ArIS The data used in creating the attached one page of regression analysis JMP-printout come from a study on the operation of a plant for the oxidation of ammonia to nitric acid. The process variables studied were x1air flow x2cooling water inlet temperature and the response variable was y = stack loss. * JMP output attached here, JMP-output.pdf Rounding 2.8431 to the nearest hundredth would give 2.84 (two decimal places) * Use appropriate tables (attached here) to answer your questions. (t-table.pdf, F-table.pdf Part 1: Use the first regression analysis (relating y to x1) output in answering the questions (a)- (c) below. ** Note that use ,-57.765 and (x1,-%)2 = 871.06 .Explanation / Answer
(g)
Observed t value:
t = 3.73
df = 14
The p-value : 0.0023
Since p-value is less than 0.05 so this variable is signficant to the model.
correct option is a.