Please label each answer clearly Options under \"Determine a conclusion\": (Do n
ID: 3323775 • Letter: P
Question
Please label each answer clearly
Options under "Determine a conclusion": (Do not reject, Reject) the null hypothesis. There (Is evidence, Is insufficient evidence)
Options for part C: (Yes,, No,) the result in (b) (Does not make, Makes) it appropriate to...
Does it take more effort to be removed from an email list than it used to? A study of 100 large online retailers revealed the data table to the right. Complete parts (a) through (c) below Need three or more clicks to be removed Year 2009 2008 Yes 31 0 69 92 Normal table, Click he lick here to view pag a. Set up the null and alternative hypotheses to try to determine whether it takes more effort to be removed from an email list than it used to Let population 1 correspond to 2009 and population 2 correspond to 2008. Choose the correct answer below. Normal table b. Conduct the hypothesis test defined in (a), using the 0.05 level of significance Calculate the test statistic, ZSTAT ZSTAT-L (Round to three decimal places as needed.) Find the rejection region. Select the correct answer below and fill in any answer boxes in your choice (Round to three decimal places as needed.)Explanation / Answer
Given that,
sample one, x1 =31, n1 =100, p1= x1/n1=0.31
sample two, x2 =8, n2 =100, p2= x2/n2=0.08
null, Ho: p1 <= p2
alternate, H1: p1 > p2
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.645
since our test is right-tailed
reject Ho, if zo > 1.645
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.31-0.08)/sqrt((0.195*0.805(1/100+1/100))
zo =4.105
| zo | =4.105
critical value
the value of |z | at los 0.05% is 1.645
we got |zo| =4.105 & | z | =1.645
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail - Ha : ( p > 4.1049 ) = 0.00002
hence value of p0.05 > 0.00002,here we reject Ho
ANSWERS
---------------
a.
null, Ho: p1 <= p2
alternate, H1: p1 > p2
b.
test statistic: 4.105
critical value: 1.645
c.
|zo| =4.105 & | z | =1.645
| zo | > | z |
decision: reject Ho
p-value: 0.00002
we have enough evidence to support the claim that population proportion of large online retailers who require three or more clicks to be removed from a email list is greater in 2009 than in 2008