Please explain the reasoning behind this. 29. In a study of the relationship bet
ID: 3324119 • Letter: P
Question
Please explain the reasoning behind this.
29. In a study of the relationship between oxygen content (x) and ultimate testing strength (y) of welds, data were obtained on 29 welds. Oxygen content was measured in parts per thousand (ppt), and strength was measured in ksi Lower 95% | Upper 95% 4E-07 33.8765047165.68274335 0.00239082) 6.560892395| 27.28484861 p-value Coefficients Standard Error 49.77962403 | 7.750698311 | 6.42 8589| 7 t Stat Intercept Oxygen content | 16.9228705 | 5.050114045 3.35098779 (a) Predict the ultimate testing strength if the oxygen content is 1.6 ppt. (2pts) 7b, 85 o 2 ksi (b) Give an interpretation of R2-0.293732093. (3pts) 29,3 % af%2 variation,in ultimate testing shenat f wlds s explained by he lnear relationship with oxygen content ing shength (c) State the hypotheses to test for a linear relationship between ultimate testing strength and oxygen content (3pts) Ho (d) In the table, circle the appropriate test statistic and p-value to test the above hypotheses. (1pt) (e) Using the 0.05 significance level, make a decision about Ho. (2pts) esect ffaExplanation / Answer
Decision Rule Based on P-value :-
To use a P-value to make a conclusion in a hypothesis test, compare the P-value with level of significance
1. If P-value , then reject H0.
2. If P-value > , then fail to reject H0.
Here P-value = 0.00239082
From 1 decision Rule P-value is less than =0.05 level of significance. So reject the null hypothesis (Ho).