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Please label all answers very clearly Options under \"Determine a conclusion\":

ID: 3324526 • Letter: P

Question

Please label all answers very clearly

Options under "Determine a conclusion": (Do not reject, Reject) the null hypothesis. There (Is evidence, Is insufficient evidence)

Options for part C: (Yes,, No,) the result in (b) (Does not make, Makes) it appropriate to...

Does it take more effort to be removed from an email list than it used to? A study of 100 large online retailers revealed the data table to the right. Complete parts (a) through (c) below Need three or more clicks to be removed Year 2009 2008 Yes 45 19 0 81 Click here to view page 1 of the Normal table, Click here to view page 2 of the Normal table. a. Set up the null and alternative hypotheses to try to determine whether it takes more effort to be removed from an email list than it used to Let population 1 correspond to 2009 and population 2 correspond to 2008. Choose the correct answer below. b. Conduct the hypothesis test defined in (a), using the 0.05 level of significance Calculate the test statistic, ZSTAT ZSTAT-L (Round to three decimal places as needed.) Find the rejection region. Select the correct answer below and fill in any answer boxes in your choice (Round to three decimal places as needed.) TAT TAT STAT

Explanation / Answer

Given that,
sample one, x1 =45, n1 =100, p1= x1/n1=0.45
sample two, x2 =19, n2 =100, p2= x2/n2=0.19
null, Ho: p1 <= p2
alternate, H1: p1 > p2
level of significance, = 0.05
from standard normal table,right tailed z /2 =1.645
since our test is right-tailed
reject Ho, if zo > 1.645
we use test statistic (z) = (p1-p2)/(p^q^(1/n1+1/n2))
zo =(0.45-0.19)/sqrt((0.32*0.68(1/100+1/100))
zo =3.941
| zo | =3.941
critical value
the value of |z | at los 0.05% is 1.645
we got |zo| =3.941 & | z | =1.645
make decision
hence value of | zo | > | z | and here we reject Ho
p-value: right tail - Ha : ( p > 3.9412 ) = 0.00004
hence value of p0.05 > 0.00004,here we reject Ho
ANSWERS
---------------
a.
null, Ho: p1 <= p2
alternate, H1: p1 > p2
b.
test statistic: 3.941
option :A
critical value: 1.645
c.
decision: reject Ho
p-value: 0.00004
Yes,
we have enough evidence to support the claim that the population proportion of larger online retailers who require 3 or more clicked removed from a email list is greater than 2009 than 2008