Foer each of the following statements, determine if it\'s true or false and expl
ID: 3326109 • Letter: F
Question
Foer each of the following statements, determine if it's true or false and explain why
a) If you select 17 names and each name has probability 1/2 of being a boy name and 1/2 of being a girl name. What is the probability that 15 are for boys and 2 are for girls: Answer is .001:______
b) If a two factor analysis of Variance produces a statistically significant interaction, then the significance of the main effects is not related to the significance of the interaction:______________
c) No expected cell frequencies less than 5 and mutually exclusive categories and independent observations are the restrictions needed to be met for the Goodness of Fit Chi Square to provide valid results:_____________
Explanation / Answer
Answer:
a) If you select 17 names and each name has probability 1/2 of being a boy name and 1/2 of being a girl name. What is the probability that 15 are for boys and 2 are for girls: Answer is .001: TRUE
Explanation: Probability of 15 for boys and 2 for girls can be determined as:
17C15*(1/2)15*(1/2)2 = 136*(1/131072) = 0.001
b) If a two factor analysis of Variance produces a statistically significant interaction, then the significance of the main effects is not related to the significance of the interaction: TRUE
Explanation:If there is a significant interaction, then it is not meaningful to test for any main effect. Interpreting the main effects in the presence of a statistically significant interaction could lead to erroneous conclusions.
c) No expected cell frequencies less than 5 and mutually exclusive categories and independent observations are the restrictions needed to be met for the Goodness of Fit Chi Square to provide valid results: TRUE
Explanation: chi-square goodness of fit test is considered to be valid if each of the expected cell frequencies is atlease 5, the observations are independent and categories are mutually exclusive. When the expected frequency in a cell of a table is less than 5 then in such cases chi-square test can lead to erroneous conclusions.