Three experiments investigating the relation between need for cognitive dlosure

Question

Three experiments investigating the relation between need for cognitive dlosure and persuasion were performed. Part of the study involved administering a "need for closure scale to a group of students enrolled in an introductory psychology course. The "need for dlosure scale" has scores ranging from 101 to 201. For the 79 students in the highest quarbile of the distribution the mean score was x-176.70. Assume a population standard dev ation of 29. These tudents were a dansfied n Ngh on ther need for sen, Anne that the 79 students represent a random sample of all students vho are classi ed as high on their need for dosure. Find a 95% confidence interval for the population mean score- on the "need for closure scale for all students with a high need for closure. (Round your answers to two decimal places) lower limit 174 upper limit178 My Three experiments investigating the relation betiween need for cognitive closure and persuasion were performed. Part of the study involved administering a "need for closure scale to a group of students enrolled in an introductory paychology course. The "need for closure scale" has scores ranging from 101 to 201. For the 70 students in the highest quartle of the dstrbution, te mean score was x 1 761C. Assume a population standard deva on of ·7.62. These students were all classified as high on their need for closure. Assume that the 70 students represent a random sample of all students who are classified as high on their need for closure. How large a sample is needed if we wish to be 99% confident chat the sample mean score is within 1.6 points of the population mean score for students who are high on the need for closure? (Round your answer up to the nearest whole number students

Explanation / Answer

Since you have posted multiple questions,i would be attaching answer for first problem you posted.Can you please try to post one question at a time for next set of problems ?

For 95% confidence, Z/2 =1.96

CI = x ± Z/2 × (/n)

   = 176.7 ± 1.96 x (8.29/79)

   = 176.7 ±1.96x0.93270

   =176.7 ± 1.828

So lower limit =176.7-1.828 =174.87

upper limit =176.7+1.828 =178.53

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