For an experiment you take rat liver and perform fractionation by centrifugation

Question

For an experiment you take rat liver and perform fractionation by centrifugation. The liver is diluted by 1/100 during this process. You then further dilute the sample by 1/5 and 1/20 during assay preparation. If you are performing an acid phosphatase assay and have a sample with an absorbance/min reading of 0.9, what would the relative activity (RA) of the enzyme be?

extinction coefficient and length are constant, so do not factor into equation.

Would the answers be?

1. RA=.9(1/100)(1/5) = 1.8e-3

2. RA=.9(1/100)(1/200)= 4.5e-5

Explanation / Answer

The answer would be:

RA=.9(1/100)(1/5) = 1.8e-3

Related Questions

Navigate

• Browse (All)
• Browse F
• Subjects