Secure ! https://www.mathxlcom/studen Robin Bradshaw | 1/29/18 10:08 PM Math 200
ID: 3354472 • Letter: S
Question
Secure ! https://www.mathxlcom/studen Robin Bradshaw | 1/29/18 10:08 PM Math 2000-07 SP18 Save Homework: 3.3 Homework HW Score: 526%, 2 of 38 pts E Question Help variance, and standard deviation Score: 0 of 4 pts 30f 13 (2 complete) 3.3.14 Listed below are the ar for the set of data. What would be the values of the measures of variation if the tuna sushi contained no mercury? 0.76 0.87 0.68 1.15 0.95 0.53 1.11 The range of the sample data isppm. (Round to three decimal places as needed.) Enter your answer in the answer box and then click Check Answer Clear AlExplanation / Answer
Answer - 3:
Range = Maximum - Minimum
In the given data,
Minimum = 0.53
Maximum = 1.15
Hence,
Range = 1.15 - 0.53 = 0.62