For questions 14-18, consider the table below with opinions about the Affordable

Question

For questions 14-18, consider the table below with opinions about the Affordable Care Act broken down by age categories. 18 to 29 76 Approve Disapprove 66 No Opinion 8 Total 30 to 49 92 94 12 200 50 to 64 72 94 65+ 29 40 Total 269 294 35 150 175 75 600 14. How many 18-29 year-olds in this survey would be expected to disapprove of the Affordable Care Act if age and opinion were independent? a) (66/150)*(66/294) 0.098 b) (150/600) (294/600) 600 73.5 c) 66 d) (66/150)*(66/294)*600- 59.27 e) None of the above 15. Can we use our chi-squared test for this data? a) No, because we expect a value of at least five in each box. b) No, because we expect a value of less than five in some boxes. c) Yes, because we expect a value of at least 5 in each box d) Yes, because we expect a value of less than five in some boxes. 16. Assuming we can use the chi-squared distribution for this test, how many degrees of freedom would we have? a) 3 b)4 c)6 d)12 e none of these 17. If one of our assumptions is not met, which of the following is an option to still use the chi squared distribution? a) Decrease the degrees of freedom for our chi-square statistic. b) Separate columns or rows so that each box has an expected count less than five. c) Use a z distribution instead d) Combine columns or rows so that each box has at an expected count of at least five 18. If we can perform a chi-squared distribution and we get a p-value of 0.002, what is an appropriate statistical interpretation of that p-value? a) Assuming the null hypothesis is correct, there is only a 0.2% chance of getting a result this extreme. Such a low p-value is generally considered good evidence to reject the null. b) Assuming the alternative hypothesis is correct, there is only a 0.2% chance of getting a result this extreme. Such a low p-value is generally considered good evidence to reject the null. c) Assuming the null hypothesis is correct, there is only a 0.2% chance of getting a result this extreme. Such a large p-value is generally not generally considered enough evidence to reject the null. d) Assuming the alternative hypothesis is correct, there is only a 0.2% chance of getting a result this extreme. Such a large p-value is generally not generally considered enough evidence to reject the null. e) none of these

Explanation / Answer

14)

option B is correct

15)

option B

16)

degree of freedom =(rows-1)*(columns-1) =(3-1)*(4-1) =6

option C

17)option D

18)option A

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