Anova: Single Factor COMMENT ON THE VALIDITY OF THIS TEST RESULT SUMMARY Groups

Question

Anova: Single Factor COMMENT ON THE VALIDITY OF THIS TEST RESULT SUMMARY Groups Count Sum Average Variance Standard Deviation DOUGHERTY 4 270 67.5 91.66666667 9.574271078 GUJARATI 4 335 83.75 1406.25 37.5 WOOLDRIDGE 4 320 80 1016.666667 31.88521078 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 579.1667 2 289.583333 0.345484673 0.716867354 4.256494729 Within Groups 7543.75 9 838.194444 Total 8122.917 11 Anova: Single Factor COMMENT ON THE VALIDITY OF THIS TEST RESULT SUMMARY Groups Count Sum Average Variance Standard Deviation DOUGHERTY 4 270 67.5 91.66666667 9.574271078 GUJARATI 4 335 83.75 1406.25 37.5 WOOLDRIDGE 4 320 80 1016.666667 31.88521078 ANOVA Source of Variation SS df MS F P-value F crit Between Groups 579.1667 2 289.583333 0.345484673 0.716867354 4.256494729 Within Groups 7543.75 9 838.194444 Total 8122.917 11

Explanation / Answer

here null hypothesis H0: mean(dougherty)=mean(gujrati)=mean(wooldridge)

alternate hypothesis H1: atleast one mean is different to others

from the anova the the F-calculated 0.345484673 is less than F-critical 4.256494729, so we fail to reject H0 and conclude that there is no difference among groups.

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