In a study of children with a particular disorder, parents were asked to rate th
ID: 3358608 • Letter: I
Question
In a study of children with a particular disorder, parents were asked to rate their child on a variety of items related to how well their child performs different tasks. One item was as difficulty organizing work rated on a five-point scale of 0 to 4 with corresponding t not at all" and 4 corresponding to very much. Theme rating or 282 o with the disorder was reported as 2.34 with a standard deviation of 1.13. (Round your answers to four decimal places.) Compute the 90% confidence interval ( 2.2289 , 2.4510 ) Compute the 95% confidence interval (2.2081 × , 2.4718 X ) Compute the 99% confidence interval. 2.1664X2.5136 x Explain the effect of the confidence level on the width of the interval 0 we see that the width of the interval increases with confidence level We see that the width of the interval decreases with confidence level We see that the width of the interval does not change with confidence level.Explanation / Answer
Mean = 2.34
Stdev = 1.13
For 90% Z is 1.645, the 90% CI is given by : 2.34+/- 1.645*1.13 = .48115 to 4.1989
For 95% Z is 1.96, the 95% CI is given by : 2.34+/- 1.96*1.13 = .1252 to 4.5548
For 99% Z is 2.56, the 99% CI is given by : 2.34+/- 2.56*1.13 = -.5528 to 5.2328
We see that the width of interval increases with confidence level