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QUESTION9 The data table below contains the amounts that a sample of nine custom

ID: 3364542 • Letter: Q

Question

QUESTION9 The data table below contains the amounts that a sample of nine customers spent for lunch (in 4.22 5.01 5.82 6.52 7.33 7.42 8.61 8.46 9.73 Is there any evidence that the mean amount spent for lunch is different from $6.50 Using the table below calculate the STAT dollars) at a fast Descriptive Statistics Mean 7.013333 0.59828 7.33 Standard Error Median Mode Standard Deviation 1.79484 Sample Variance 3.2214 Kurtosis Skewness Range Minimum Maximum Sum Count HN/A -0.84277 0.12253 5.51 4.22 9.73 63.12 0.9023 0.8580 0.8660 0.9053

Explanation / Answer

Below are the null and alternate hypothesis
H0: mu = 6.5
H1: mu not equals 6.5

Test statistics, t = (xbar - mu)/SE
t = (7.0133 - 6.5)/(1.79484/sqrt(9))
t = 0.8580

Option B is correct