8. The Committee on Student Life did a survey of 417 students regarding satisfac
ID: 3366477 • Letter: 8
Question
8. The Committee on Student Life did a survey of 417 students regarding satisfaction with studen t govemment and class standing. The results are shown in the table below Freshman SophomoreJunior Senio (Sen) 12 38 65 115 ROW TOTAL (Soph) Not satisfied (NS) Neutral (Ne) Satisfied (S) COLUMN TOTAL 17 61 23 101 35 49 103 23 32 43 98 166 180 417 GRAND TOTAL Assume that the sample represents the entire population of customers. Find the probability that a student is: a. P(S) b. P(Sen) c. P(S | Sen) d. P(S and Sen) e. P(S or Sen)Explanation / Answer
a) P(S) = 180 / 417 = 0.43165
b) P(Sen) = 115/417 = 0.2758
c) P(S/Sen) = P(S and Sen) / P(Sen)
= (65/417) / (115/417) = 65/115 = 0.5652
d) P(S and Sen) = 65/417 = 0.15587
e) P(S or Sen) = P(S) + P(Sen) - P(S and Sen)
= 0.43165 + 0.2758 - 0.15587 = 0.55158
f) P(Ne / F) = P(Ne and F) / P(F)
= (61/417) / (101/417) = 61/101 = 0.60396