Three friends go out for a cup of coffee. To choose the one who will pay for the
ID: 3371285 • Letter: T
Question
Three friends go out for a cup of coffee. To choose the one who will pay for the coffee play the following game: Everyone throws a coin in the air, and the person who obtains a different result has to pay, if everyone gets the same result they continue to launch until someone loses. The coin is not balanced, the probability of face is 0.60.A)Calculate the probability that less than 5 games have to be played before one of them has to pay.
Three friends go out for a cup of coffee. To choose the one who will pay for the coffee play the following game: Everyone throws a coin in the air, and the person who obtains a different result has to pay, if everyone gets the same result they continue to launch until someone loses. The coin is not balanced, the probability of face is 0.60.
A)Calculate the probability that less than 5 games have to be played before one of them has to pay.
Three friends go out for a cup of coffee. To choose the one who will pay for the coffee play the following game: Everyone throws a coin in the air, and the person who obtains a different result has to pay, if everyone gets the same result they continue to launch until someone loses. The coin is not balanced, the probability of face is 0.60.
A)Calculate the probability that less than 5 games have to be played before one of them has to pay.
Explanation / Answer
here probability that all three have same result=P(all 3 have heads)+P(all 3have tails)
=(1/2)*(1/2)*(1/2)+(1/2)*(1/2)*(1/2)=1/4
hence probability that less than 5 games have to be played before one of them has to pay
=1-P(till 4 round all have same result)=1-(1/4)3 =0.984375