Porosity readings on construction paper were recorded for paper from four rolls
ID: 3372054 • Letter: P
Question
Porosity readings on construction paper were recorded for paper from four rolls taken at random from each of three lots. The results were as follows Lot Roll 1 23 4 5 6 7 8 9 10 11 12 1.5 1.5 2.7 3.0 19 2.3 1.8 1.9 2.5 3.2 1.4 7.8 1.7 1.6 1.9 2.4 1.5 2.42.9 3.5 2.9 5.5 1.5 5.2 1.6 1.7 2.0 2.6 2.1 2.4 4.7 2.8 3.3 7.1 3.4 5.0 Source MS 020 021 022 EMS 023 024 025 df 014 015 016 017 018 019 0 What is the value for Q18 O A. 27.42 B. 21.80 ? ?. 36.38 D. 85.60 What is the value for Q17 OA. 36.28 B. 21.80 O C. 85.60 O D. 27.42 What is the value for Q16 O A. 9 O C. 24 O D. 2Explanation / Answer
Solution:
We use excel to compute the ANOVA table. In excel, we use two factor anova with replication in data analysis in data
We take rows per sample = 3. The following output is shown:
1. Option C is correct.
The value of Q18 is SS(factor 2) + SS (interaction) = 14.8278 + 21.3956 = 36.2233. The closest answer is 36.38
2. Option D is correct.
The value of Q17 is SS (factor 1 ) = 27.0822. The closest answer is 27.42.
3. Option C is correct.
The value of Q16 is df (error) = 24.
Two factor ANOVA Factor 2 Means: Column 1 Column 2 Column 3 Column 4 I 1.600 1.667 #### 2.667 2.033 Factor 1 II 1.833 2.367 #### 2.733 2.517 III 2.900 5.267 #### 6.000 4.067 2.111 3.100 #### 3.800 2.872 3 replications per cell ANOVA table Source SS df MS F p-value Factor 1 27.0822 2 13.54111 14.86 .0001 Factor 2 14.8278 3 4.94259 5.42 .0054 Interaction 21.3956 6 3.56593 3.91 .0072 Error 21.8667 24 0.91111 Total 85.1722 35