Four women’s college basketball teams are participating in a single-elimination
ID: 3380597 • Letter: F
Question
Four women’s college basketball teams are participating in a single-elimination holiday basketball tournament. If one team is favored in its semifinal match by odds of 1.95 to 1.05 and another squad is favored in its contest by odds of 2.75 to 1.25, what is the probability that:
Four women’s college basketball teams are participating in a single-elimination holiday basketball tournament. If one team is favored in its semifinal match by odds of 1.95 to 1.05 and another squad is favored in its contest by odds of 2.75 to 1.25, what is the probability that:
Explanation / Answer
Here, the probability that the favored teams win their games is
P1 = 1.95/(1.95+1.05) = 0.65
P2 = 2.75/(2.75+1.25) = 0.6875
a)
Thus,
P(both win) = 0.65*0.6875 = 0.446875 = 0.4469 [ANSWR]
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b)
P(neither win) = (1-0.65)*(1-0.6875) = 0.1094 [ANSWER]
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C)
P(At least one win) = 1 - P(neither win) = 0.8906 [ANSWER]