The melting point of each of 16 samples of a certain brand of hydrogenated veget
ID: 3389759 • Letter: T
Question
The melting point of each of 16 samples of a certain brand of hydrogenated vegetable oil was determined, resulting in a sample mean of 94.32. Assume that the distribution of melting point is normal with = 1.20.
Test H0:=95 versus Ha:95 using a two-tailed level .01 test.
The computed value of the test statistic is:
The null hypothesis will be rejected if the computed value of the test statistic is greater than or equal to:
The null hypothesis will be rejected if the computed value of the test statistic is greater than or equal to :
Explanation / Answer
As we can see, this is a two tailed test.
Getting the test statistic, as
X = sample mean = 94.32
uo = hypothesized mean = 95
n = sample size = 16
s = standard deviation = 1.2
Thus, z = (X - uo) * sqrt(n) / s = -2.266666667 [ANSWER, TEST STATISTIC]
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Thus, getting the critical z, as alpha = 0.01 ,
alpha/2 = 0.005
zcrit = 2.575829304
Thus, The null hypothesis will be rejected if the computed value of the test statistic is greater than or equal to 2.575829304. [ANSWER]
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