Please help....detail explanation will be greatful!! Overall mean: 22.78 Overall

Question

Please help....detail explanation will be greatful!!

Overall mean: 22.78

Overall Std. Dev: 11.85

Test statistic: 0.6255

Critical Value, when alpha = 0.05: 3.68

c. Rank the data (1=lowest), using the average of the ranks for any set of tied observations. then find the Kruskal-Wallis statistic

then adjust the value of H by dividing it by

where t_i is the number of observations that are tied for a given set of ranks. Compare this test statistics with the critical value of chi-Square (with alpha =0.05), which has k-1 degrees of freedom to decide whether to accept or reject the null hypothesis.

Observation Long Island Sound Great South Bay Shinnecock Bay 1 32 54 15 2 23 27 18 3 14 18 19 4 42 11 21 5 13 10 28 6 22 34 9 Mean 24.33 25.67 18.33 Standard Dev. 11.08 16.69 6.31

Explanation / Answer

So the Kruskal-Wallis statistic:

H=0.851756

So accept the null hypothesis.

Median n Avg. Rank 22.50 6 10.67 Long Island Sound 22.50 6 9.92 Great South Bay 18.50 6 7.92 Shinnecock Bay 20.00 18 Total

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