The regression equation is reported as y=21.42x+61.78 and the r2=0.36. What is t
ID: 3442378 • Letter: T
Question
The regression equation is reported as
y=21.42x+61.78
and the r2=0.36.
What is the correlation coefficient for this data set?
r =
y=2.057x+45.151
with a correlation coefficient of r=0.748 (which is significant at =0.01). You want to predict what value (on average) for the explanatory variable will give you a value of 120 on the response variable.
What is the predicted explanatory value?
x =
y=3.572x61.153
with a correlation coefficient of r=0.654. You want to predict what value (on average) for the response variable will be obtained from a value of 140 as the explanatory variable.
What is the predicted response value?
y =
y=1.658x0.913
with a correlation coefficient of r=0.666. You want to predict what value (on average) for the response variable will be obtained from a value of 100 as the explanatory variable.
What is the predicted response value?
y =
(Report answer accurate to one decimal place.)
Explanation / Answer
What is the correlation coefficient for this data set?
r= srqt (0.36) = 6
R = -6 is negative because if you graph the equation of regression it has a negative slope
What is the predicted explanatory value?
y=2.057x45.151
120= 2.057X - 45.151
X = 36.4
What is the predicted response value?
y=3.572x61.153
Y = 3.572*140 - 61.153
Y= 438.9
What is the predicted response value?
y=1.658x0.913
Y = -1.658*100 - 0.913
Y= -166.7