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McGrow-Hial Connect Google W WordPress ICONUl EmailSign In to EBCConnect Problem 7-16 The diagram below represents a process where two components are made at stations A1 and A2 (one component is made at A1 and the other at A2). These components are then assembled at station B and moved through the rest of the process, where some additional work is completed at stations C, D, and E. Assume that one and only one person is allowed at each station. Assume that the times given below for each station represent the amount of work that needs to be done at that station by that person, with no processing time variation. Assume that inventory is not allowed to build in the system. 20 min 0.90 min130min 120min 1.10 min A2 1.10 min. What is the average hourly output of the process when it is in normal operation? (Round your answer to the nearest whole number.) Average hourty output References eBook & Resources Worksheet Dimiculty Challenge Problem 7-16 Learning Objective: 07-03 Analyze stimple Type here to search

Explanation / Answer

Workstation C has the maximum processing time. Therefore, it is the bottleneck.

Therefore process capacity is equal to the capacity of workstation C. Cycle time = 1.3 minutes

Hourly output of the process = 60 minutes per hour / Cycle time = 60/1.3 = 46.15 ~ 46 units  (rounded off to the whole number)

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