Please help, I will rate life saver and give points Answer (he following questio

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Please help, I will rate life saver and give points

Answer (he following questions on binary numbers: Compute the result of (73)10 - (159)10 using 2's complement representation with an odd parity bit in the most significant bit. Note that all your numbers should be represented using the minimal number of bits without causing overflow during calculation. The solutions to the quadratic equation x2-(0101)x + (0001) = (0000) are x = (1000) andx = (1100), where all the numbers are weighted decimal codes. Assume that all the weights of the code are positive and different What is the decimal value of (1101)?

Explanation / Answer

(73)10 - (159)10

7*10^1+ 3*10^0- 1*10^2-5*10^1-9*10^0

= -1*10^2+2*10^1-6*10^0

=(-86)10

b) x^2-(0101)x+1001=0000

solutions are x= 1000, 1100

all are weighted decimal codes

so

(x-1000)(x-1100)=0

x^2-x(1000+1100)+(1000)(1100)=0000

so

0101=1000+1100

so

a^2+a = a^3+a^3+a^2

a=2a^3

2a^2=1 (as a cannot be zero)

a^2=1/2

also

1001=(1000)*(1100)

a^3+1 = (a^3)*(a^3+a^2)

a/2+1= a/2*(a/2+1/2)

a/2+1= 1/8+a/4

a/4= -7/8

as a cannot be negative

a^2=1/2 is the solution

1101= a^3+a^2+1 = a/2+3/2

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