Convert the following C program to MIPS program. Assuming that i, j, k, f, are s

Question

Convert the following C program to MIPS program. Assuming that i, j, k, f, are stored in registers $s0, $s1, $s2, $s3 already.

A.) f = i + j - k;

B.) f = i + ( j - 8 );

C.) f = -i + ( j + 3); (Hint: $zero)

D.) f = i * 4; (Hint: Relationship between multiplication and shift)

E.) f = i/2 + 2;

F.) f = i;

G.) f = -i;

H.) i++;

If anyone can give a little more explanation along with the answer that would be fantastic. As I missed a class on MIPS and it has proven harder to make up than I expected. Thanks!

Explanation / Answer

Instrunctions:

Assuming that i, j, k, f, are stored in registers $s0,$s1, $s2, $s3 already

f = i + j

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