In a bottomland hardwood forest, there is a population of 5000 Timber Rattlesnak
ID: 35860 • Letter: I
Question
In a bottomland hardwood forest, there is a population of 5000 Timber Rattlesnakes. 2500 Timber Rattlesnakes that are homozygous dominant (RR) for a bright orange color that runs down the vertebral column. 1500 are heterozygous (Rr) for a pale yellow color. 1000 Timber Rattlesnakes that are homozygous recessive (rr) for no color down the vertebral column. Based on this information, answer the following questions.
i.What is the genotypic frequency for RR?
ii.What is the genotypic frequency for Rr?
iii.What is the genotypic frequency for rr?
iv.What is p (I am looking for a number)?
v.What is q (I am looking for a number)?
vi.Is this population evolving? explain
Explanation / Answer
Ans.
Given,
Population = 5000
Homozygous Dominant (RR) = 2500
Heterozygous Dominant (Rr) = 1500
Homozygous Recessive (rr) = 1000
i.What is the genotypic frequency for RR?
Genotypic Frequency = Genotype / Poulation
= 2500 / 5000
= 0.5
ii.What is the genotypic frequency for Rr?
Genotypic Frequency = Genotype / Poulation
= 1500 / 5000
= 0.3
iii.What is the genotypic frequency for rr?
Genotypic Frequency = Genotype / Poulation
= 1000 / 5000
= 0.2
iv.What is p (I am looking for a number)?
' p ' is actually Allele Frequency for Dominant Allele ' R '
Allele frequency = no. of Alleles / Total no. of Alleles
Now,
no. of ' R ' alleles = 2500 of RR + 1500 of Rr
= 2500 * 2 + 1500 * 1 (RR contains 2 R alleles and Rr conatins 1 R allele)
= 6500
Total no. of Alleles = 5000 * 2 = 10,000 alleles
Allele frequency = no. of Alleles / Total no. of Alleles
= 6500 / 10000
p = 0.65
v.What is q (I am looking for a number)?
' q ' is actually Allele Frequency for Recessive Allele ' r '
Allele frequency = no. of Alleles / Total no. of Alleles
Now,
no. of ' r ' alleles = 1000 of rr + 1500 of Rr
= 1000 * 2 + 1500 * 1 (rr contains 2 r alleles and Rr conatins 1 r allele)
= 3500
Total no. of Alleles = 5000 * 2 = 10,000 alleles
Allele frequency = no. of Alleles / Total no. of Alleles
= 3500 / 10000
p = 0.35
vi.Is this population evolving? explain
No, Population is not Evolving.
This Population is in Hardy-Weinberg Equilibrium.
Allele frequency,
p + q = 1 (satisfies Hardy-Weinberg Equilibrium)
0.65 + 0.35 = 1
Genotype frequency,
p2 + q2 + 2pq= 1 (satisfies Hardy-Weinberg Equilibrium)
0.5 + 0.2 +0.3 = 1
Therefore, Population is in Equilibrium (as it satisfies Hardy-Weinberg Equilibrium)
Therefore, Not Evolving.