Part 4: Expanded Network Suppose the company has expanded and acquired a Class B

Question

Part 4: Expanded Network Suppose the company has expanded and acquired a Class B address, 172.16.0.0. The company needs to create a subnetting scheme to provide the following: Subnet A with at least 3600 hosts Subnet B with at least 6120 hosts Subnet C with at least 500 hosts Given this Class B network address and these requirements, answer the following questions: What is the minimum number of bits that can be borrowed? What is the subnet mask in CIDR format? How many usable hosts are there? Give the beginning and ending IP addresses for each subnet: a. b. c. d. Subnet NumberSubnet Address First Usable HostLast Usable Host AddressAddress Broadcast Address

Explanation / Answer

Dear Student,

here is the answer...

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The given address is a class B address.

IP address = 172.16.0.0

The default subnet mask = 255.255.0.0

Now if we want to create subnetworks from this given network then we need to borrow some bits from the host bits to create subnetworks.

1: WE NEED A SUBNET WITH MINIMUM 3600 HOSTS.

If we borrow 4 bit from the host bits.

then given IP address with CIDR notation become = 172.16.0.0/20

subnet mask = 11111111.11111111.11110000.00000000

number of subnet = 24 = 16

block size = 256 - 240 = 16       i.e 0, 16, 32.....256.

host bits remaining = 32-20 = 12

since 212 = 4096- 2 = 4094 hosts

while we need 3600 host so now our requirement fullfilled.

hence

Minimum number of bits that can be borrowed = 4

Sunet mask in CIDR Format = 172.16.0.0/20

Usable Hosts = 4094

Beginning Address = 172.16.0.1

Ending Address = 172.16.15.254

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1: WE NEED A SUBNET WITH MINIMUM 6120 HOSTS.

If we borrow 3 bit from the host bits.

then given IP address with CIDR notation become = 172.16.0.0/19

subnet mask = 11111111.11111111.11100000.00000000

number of subnet = 23 = 8

block size = 256 - 224 = 32      i.e 0, 32, 64.....256.

host bits remaining = 32-21 = 13

since 213 = 8192- 2 = 8190 hosts

while we need 6120 host so now our requirement is fullfilled.

hence

Minimum number of bits that can be borrowed = 3

Sunet mask in CIDR Format = 172.16.0.0/19

Usable Hosts = 8190

Beginning Address = 172.16.0.1

Ending Address = 172.16.31.254

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1: WE NEED A SUBNET WITH MINIMUM 500 HOSTS.

If we borrow 7 bit from the host bits to create a subnetwork.

then given IP address with CIDR notation become = 172.16.0.0/23

subnet mask = 11111111.11111111.11111110.00000000

number of subnet = 27 = 128

block size = 256 - 254 = 2      i.e 0, 2, 4.....256.

host bits remaining = 32-23= 9

since 29 = 512- 2 = 510 hosts

while we need 510 host so now our requirement fullfilled.

hence

Minimum number of bits that can be borrowed = 7

Sunet mask in CIDR Format = 172.16.0.0/23

Usable Hosts = 510

Beginning Address = 172.16.0.1

Ending Address = 172.16.1.254

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Here is the complete Table..

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kindly Check and Verify Thanks...!!!

Subnet Number Subnet Address First Usable Host Address Last Usable Host Address Broadcast Address A 172.16.0.0/20 172.16.0.1 172.16.15.254 172.16.15.255 B 172.16.0.0/19 172.16.0.1 172.16.31.254 172.16.16.255 C 172.16.0.0/23 172.16.0.1    172.16.1.254 172.16.1.255

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