int sillyone(int n) { if (n <= 1) return n; else return sillyone(n-1) + sillyone

Question

int sillyone(int n)
{
if (n <= 1)
return n;
else
return sillyone(n-1) + sillyone(n-1);
}

int sillytwo(int n)
{
if (n <= 1)
return n;
else
return 2 * sillytwo(n-1);
}

Output of sillyone(5) is
Output of sillytwo(5) is .

# of sillyone() invocations done as part of sillyone(5) executionis .
# of sillytwo() invocations done as part of sillytwo(5) executionis .

I believe the output of sillyone(5) is 8 and the output ofsillytwo(5) is also 8. Just want to verify.
I do need the answers to the 2nd part of the test - theinvocations.

Explanation / Answer

#include using namespace std; int two =0; /*one stores the numebr of invocationsof sillyone(), two stores the number of invocations of sillytwo()*/ int sillyone(int n) { one++; //increases if sillyone()is executed    if (n

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---