Hi, I am trying to write a function to alphabetically sort a list of names. Here

Question

Hi, I am trying to write a function to alphabetically sort a list of names. Here is the function:

void abc_order(Node people[], int size)
{
int x;
int y;
int temp;

for(x=size; x>0; x--)
{
for(y=0; y<x-1; y++)
{
if(people[y].name>people[y+1].name)
{
temp = people[y+1].name;
people[y+1].name = people[y].name;
people[y].name = temp;
}

}
}

cout << "SORTED LIST ACCORDING TO LAST NAME:" << endl << endl;
for (int i = 0; i < size; i++)
{
cout << "Name: " << people[i].name << endl;
cout << "ID: " << people[i].ID << endl;
cout << "Distance: " << people[i].distance << endl << endl;
}
}



Here is the text that I am trying to sort:
April,Joe
3120
90

Matthews,Jocob
4592
88

Garfield,Kitty
8917
79

Lake,Bill
2233
85

Johnson,Jim
5672
67

Zumistan,Kim
6750
76

Larson,Mike
6718
99

Anderson,Eva
5672
80



Thank you so much! If you need to see the rest of my code to help me just let me know! Thanks!

Explanation / Answer

Hope this helps. Let me know if you have any questions. Please rate. :) You were very close!! See the two changes in comments below. void abc_order(Node people[], int size) { int x; int y; // temp should be of type Node, since it is what you are swapping around Node temp; for(x=size; x>0; x--) { for(y=0; ypeople[y+1].name) { // You want to swap all the data, not just the name, so just swap the whole Node // Set the temp Node equal to people[y+1], then reassign that Node to people[y], // then set people[y+1] back to the temp Node, and you will swap all the data at once temp = people[y+1]; people[y+1] = people[y]; people[y] = temp; } } } cout

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