trying to make statement by using p.u.t.t.y when you done making statement you w

Question

trying to make statement by using p.u.t.t.y

when you done making statement
you will need to type 'a.out'

then 'put a positive number: ' will appear and you should type 567890

then the output should appear like below

first number: 567890
inverse integer: 098765

Also, when you type 998877665544

it will appear like

first number: 998877665544
inverse integer: 445566778899

 

when you type negative number, 'you should type positive number' should be appear on the output.

the same result  'you should type positive number'  will appear if you type 0 (zero).

 

I can ONLY use loop function (repitition function) and if/if else function to make this statement

no arrays or the other function

Explanation / Answer

#!/bin/bash/ echo "Enter the number you want to check" read a d=$a if [ '0' -gt $a ] then echo "enter a positive number" else echo $a > wcf n=`echo $a | wc -c` n=`expr $n - 1` p=0 for (( i=0; ia.out echo "check the out put in the file name called a.out" fi

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