Assign it values using loops such that the first element is 3 and every element

Question

Assign it values using loops such that the first element is 3 and every element after that is the determined by the following formula a[i] = a[i-1] + (3*i) if a [i-1] is even number a[i] = a[i-1] - (2*i) if a [i-1] is an odd number 2. Print array elements with each element separated by a space 3. Compute and print the following (with formats given in double quotes): a. average of all array elements - "Average : " (value) b. maximum element - "Maximum value : " (value) c. minimum element - 'Minimum value ; " (value) d. number of elements divisible by 5 - "count of numbers divisible by 5 : " (value)

Explanation / Answer

1) Printing of elements with elements startting 3

#include <iostream>
using namespace std;

   int main()
   {
       int a[20];
       a[0]=3;
       int i;

       for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
       }else {
       a[i] = a[i-1] - (2*i);
       }
          
       for ( i = 0; i < 20; i++ )
           cout << a[i] << ' ';
       return 0;
   }

2) Printing elements with space

#include <iostream>
using namespace std;

   int main()
   {
       int a[20];
       a[0]=3;
       int i;

       for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
       }else {
       a[i] = a[i-1] - (2*i);
       }
          
       for ( i = 0; i < 20; i++ )
           cout << a[i] << " ";
       return 0;
   }

3)

a. To find the average of all array elements

#include <iostream>
using namespace std;

   int main()
   {
       int a[20];
       a[0]=3;
       int i;

       for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
       }else {
       a[i] = a[i-1] - (2*i);
       }
          
       for ( i = 0; i < 20; i++ )
          
                cout << a[i] << " ";
           float sum = 0.0, average;

  
      sum+=a[i];
          
   average=sum/20;
   cout << ' ' << "Average : " << average;
   return 0;
   }

b. To find the maximum element

#include <iostream>
using namespace std;

   int main()
   {
       int a[20];
       a[0]=3;
       int i;

       for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
       }else {
       a[i] = a[i-1] - (2*i);
       }
           if(a[0]<a[i])
           a[0]=a[i];
  
    cout << "Maximum Value : " << a[0] << ' ';
          
       for ( i = 0; i < 20; i++ )
           cout << a[i] << " ";

       return 0;
   }

c. To find the Minimum value

#include <iostream>
using namespace std;

    int main()
    {
        int a[20];
        a[0]=3;
        int i;

        for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
        }else {
        a[i] = a[i-1] - (2*i);
        }
            if(a[0]<a[i])
           a[0]=a[i];
  
    cout << "Minimum Value : " << a[i] << ' ';
          
        for ( i = 0; i < 20; i++ )
            cout << a[i] << " ";

        return 0;
    }

d. Count of numbers divisible by 5

#include <iostream>
using namespace std;

    int main()
    {
        int a[20];
        a[0]=3;
        int i,count =0;

        for ( i = 1; i < 20; i++ )
      
            if ((a[i-1])%2==0){
            a[i] = a[i-1]+ (3*i) ;  
        }else {
        a[i] = a[i-1] - (2*i);
        }
            if(a[i]%5==0)
         
           count = count++;
           cout << "Count of numbers divisible by 5 : " << count << ' ';
  
  
        for ( i = 0; i < 20; i++ )
            cout << a[i] << " ";

        return 0;
    }

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---