ARM assembly language to convert integer, 1194684 to hexadecimal. The signature

Question

ARM assembly language to convert integer, 1194684 to hexadecimal.

The signature of the routine is char*int2hex(int convert) where:

int convert = 1194684;

The output must be in the format 0Xdddddddd

I need the ARM Assembly Language NOT the C-code.

The C program is:

#include <stdlib.h>
#include <stdio.h>

extern char * int2hex( int convert ) ;

int main( int argc, char * argv[] )
{
   int convert = 1194684 ;
   char * result ;
  
   result = int2hex( convert ) ;
   printf( "Integer to hex string: %s ", result ) ;
}

Explanation / Answer

.LC0:
   string "Integer to hex string, %s "

main:
   pushq   %rbp
   movq %rsp, %rbp
   subq   $32, %rsp
   movl   %edi, -20(%rbp)
   movq   %rsi, -32(%rbp)
   movl   $1194684, -12(%rbp)
   movl   -12(%rbp), %eax
   movl   %eax, %edi
   call   int2hex
  
   movq   %rax, -8(%rbp)
   movq   -8(%rbp), %rax
   movq   %rax, %rsi
   movl   $.LC0, %edi
    movl   $0, %eax
    call   printf
  
    movl   $0, %eax
    leave
    ret

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