CSIS 3230: Computer Networking Principles Section 002, Spring 2018 Daily Work- b

Question

CSIS 3230: Computer Networking Principles Section 002, Spring 2018 Daily Work- b Name: 6) Network Address: 172.16.0.0 Number of usable hosts in each subnet: 81972 Find the following: a) Address Class: b) Default subnet mask (decimal): 255. 255, 0. O c) Default subnet mask (t d) Number of bits borrowed: 3 e) Custom Subnet mask (binary): t.niI.U0000.oO00000o f) Custom Subnet mask (decimal): ?55-455. e 24 . 0 g) CIDR Notation 172.16.0.0/1 h) Total number of subnets: 8 i) Number of hosts addresses in each subnet: j) Number of usable hosts in each subnet k) Address ranges (Network Address, Usable Host Range, Broadcast Address) 172.6. 31.0 172.. 172. lo, 04.0 172. lo. Gu.I 112. 16. 96, 0 | 172. 16?96. I ?2. 16. 128.0 | 172. le, 128.1 112 o, Io,0 172.lo, ho, 112. 16. 192.0 I72 . i92. 172.16.224.0 72.1.224 . 1 8192

Explanation / Answer

Given 172.16.0.0

netmask

a) Address Class : B

b) subnet mask : 255.255.0.0

c)subnet mask (binary): 11111111.11111111.00000000.00000000

d)Number of bits borrowed: 3

i)Number of host addresses in each subnet = 65,534

j)number of usable hosts = 2^16-2 = 65,534

k) N/w Address: 172.16.0.0

Host Range 172.16.0.1 to 172.31.255.254

Broadcast address : 172.31.255.255

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