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CS homework language C Homework: Read rocket.txt. It is on the dropbox. Use an a

ID: 3816728 • Letter: C

Question

CS homework language C

Homework: Read rocket.txt. It is on the dropbox. Use an array and get the max acceleration. print it. Also, print another file(report.txt) of all of the acceleration values that are positive.

rocket.txt:

24
   1.0000000e+01   2.9265380e+03   5.0821200e+02   4.3231640e+01
   2.0000000e+01   1.0170240e+04   9.2798610e+02   4.0723180e+01
   3.0000000e+01   2.1486260e+04   1.1832420e+03   1.0328000e+01
   4.0000000e+01   3.3835080e+04   1.1882285e+03 -9.3307000e+00
   5.0000000e+01   4.5250830e+04   1.0899705e+03 -1.0320900e+01
   6.0000000e+01   5.5634490e+04   9.8935650e+02 -9.8019000e+00
   7.0000000e+01   6.5037960e+04   8.9134700e+02 -9.8000000e+00
   8.0000000e+01   7.3461430e+04   7.9334750e+02 -9.7999000e+00
   9.0000000e+01   8.0904910e+04   6.9534750e+02 -9.8001000e+00
   1.0000000e+02   8.7368380e+04   5.9734700e+02 -9.8000000e+00
   1.1000000e+02   9.2851850e+04   4.9934700e+02 -9.8000000e+00
   1.2000000e+02   9.7355320e+04   4.0134750e+02 -9.7999000e+00
   1.3000000e+02   1.0087880e+05   3.0334400e+02 -9.8008000e+00
   1.4000000e+02   1.0342220e+05   2.0534500e+02 -9.7990000e+00
   1.5000000e+02   1.0498570e+05   1.3402000e+02 -4.4660000e+00
   1.6000000e+02   1.0610260e+05   2.6304000e+02   3.0270000e+01
   1.7000000e+02   1.1024650e+05   6.7618500e+02   5.2359000e+01
   1.8000000e+02   1.1962630e+05   1.2929950e+03   7.1003000e+01
   1.9000000e+02   1.3610640e+05   2.1234700e+03   9.5092000e+01
   2.0000000e+02   1.6209570e+05   3.1700000e+03   1.1421400e+02
   2.1000000e+02   1.9950640e+05   3.8340050e+03   1.8587000e+01
   2.2000000e+02   2.3877580e+05   3.8779450e+03 -9.7990000e+00
   2.3000000e+02   2.7706530e+05   3.7799500e+03 -9.8000000e+00
   2.4000000e+02   3.1437480e+05   3.6819500e+03 -9.8000000e+00

Explanation / Answer

/*
* File: main.c
* Author: anandan
*
* Created on 13 April, 2017, 11:12 AM
*/

#include <stdio.h>
#include <stdlib.h>

#define FLIMIT 40
#define ILIMIT 96
/*
*
*/
int main(int argc, char** argv) {
  
FILE *ifptr, *ofptr;
char infileName[FLIMIT];
char outfileName[FLIMIT];
double values[ILIMIT];
do{
printf("Enter the name of the input file (max 40 characters) : ");
scanf("%s", infileName);
ifptr = fopen(infileName, "r");
if(ifptr == NULL){
printf("Error opening %s ", infileName);
printf("Please try again. ");
}/* if ifptr */
} while(ifptr == NULL);
  
do{
printf("Enter the name of the output file (max 40 characters) : ");
scanf("%s", outfileName);
ofptr = fopen(outfileName, "w");
if(ofptr == NULL){
printf("Error opening %s ", outfileName);
printf("Please try again. ");
}/* if ofptr */
} while(ofptr == NULL);
  
double item, maxValue;
int i = 0, j;
for(i = 0; i < ILIMIT; i++){
fscanf(ifptr, "%lf", &item);
values[i] = item;
}
  
fclose(ifptr);
  
  
maxValue = values[0];
for( i = 1; i < ILIMIT; i++){
if(maxValue < values[i]){
maxValue = values[i];
}
}
printf("The maximum acceleration value is %f", maxValue);
  
j = 0;
for(i = 0; i < ILIMIT; i++){
if(values[i] > 0){
fprintf(ofptr, "%lf ", values[i]);
j++;
if(j%3 == 0){
fprintf(ofptr, " ");
}
}
}
  
  
return (EXIT_SUCCESS);
}