In CSMA/CD, after the fifth collision, what is the probability that a node choos
ID: 3821615 • Letter: I
Question
In CSMA/CD, after the fifth collision, what is the probability that a node chooses K = 4? The result K = 4 corresponds to a delay of how many seconds on a 10 Mbps Ethernet? Describe polling and token-passing protocols using the analogy of cocktail party interactions. Why would the token-ring protocol be inefficient if a LAN had a very large perimeter? How big is the MAC address space? The IPv4 address space? The IPv6 address space? Suppose nodes A, B, and C each attach to the same broadcast LAN (through their adapters). If A sends thousands of IP datagrams to B with eachExplanation / Answer
Given information is:
The probability that a node will choose k=5 , i. e = 2^5 = 32
We have to select from {0,1,2,3....31}
P= 1/32
p=0.03125
The result of k = 5 corresponds delay in seconds on a 10 Mbps Ethernet:
Given k=5
Delay = K * 512 bit times
= 5 * 512
= 2,560 bit times
2,560 bit times / 10 Mbps = 256 microseconds
By Converting microseconds to seconds:
256 microseconds /1,000,000 micros = 0.000256 Seconds