Complete the following steps to practice calculating a supernet: 1. Starting wit
ID: 3823565 • Letter: C
Question
Complete the following steps to practice calculating a supernet: 1. Starting with the network ID 192.16.20.0/24, what is the default Class C subnet mask for this network? Write this information both in decimal and in binary. 2. How many additional network bits must be used for host information in order to have about 2000 hosts per supernet? Use the same formula you learned for calculating number of hosts on a subnet. Write the new supernet mask in binary and in decimal notation. 3. What is the CIDR notation for the network ID now?Explanation / Answer
Dear Student,
Here are the answers:
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Answer No:1:
Given ID: 192.168.16.20.0/24
The given IP address belongs to class C. Network.
The default subnetmask of class C network in decimal = 255.255.255.0
The default subnetmask of class C network in binary = 11111111.11111111.11111111.00000000
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Answer No: 2.
We know that class C network can have max 254 hosts.
So we apply subnetting concept to divide a given network into subnetworks.
and we merge the sunetworks to create a supernetwork.
So to have 2000 host in our supernetwork. We have to need 11 bits for hosts.
because 211 =2048 host. so our requirement will be fullfill if we take 11 bits for the host and remaining bits for the network.
So the new supernet mask will be in binary =
11111111.11111111.11111000.00000000
(so in the above mask in binary 21, 1 bits represent the netid and the remaining 11 zero's represent the host id.)
So the the above IP address in Decimal will be = 255.255.248.0
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Answer No:3
The CIDR notation for the given network ID is now:
192.16.20.0/21 (it means 21 bits represent the netId.)
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