Question 8: In AES, let the plaintext P and key K128 be equal. a. Perform key ad

Question

Question 8: In AES, let the plaintext P and key K128 be equal. a. Perform key addition P + k0 b. What is the output of Byte Substitution Layer in Round 1? c. What is the output of Shift Rows Layer in Round 1? d. What is the output of Mix Column Layer in Round 1?
Question 8: In AES, let the plaintext P and key K128 be equal. a. Perform key addition P + k0 b. What is the output of Byte Substitution Layer in Round 1? c. What is the output of Shift Rows Layer in Round 1? d. What is the output of Mix Column Layer in Round 1?
Question 8: In AES, let the plaintext P and key K128 be equal. a. Perform key addition P + k0 b. What is the output of Byte Substitution Layer in Round 1? c. What is the output of Shift Rows Layer in Round 1? d. What is the output of Mix Column Layer in Round 1?

Explanation / Answer

Ans (a)

In advance encription standard,

we have,

P= k128 = k0

then P+k0 = 0128

Ans (b)  A = 04x4

therefore we apply S-Box to each entry of A and get B with each entry is 63

Ans (c) Since each entry of B is equal i.e. 63

we have, B' = shiftrow(B) = B

Ans (d) Since all entries of B are equal therefore we have

QB' = QB = B

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