Counting Operations to Produce Polynomials In the following section, I will pres
ID: 3866566 • Letter: C
Question
Counting Operations to Produce Polynomials In the following section, I will present you with multiple different bodies of code, and it is your job to analyze each code section and build a polynomial that represents the number of abstract operations the code performs. Once we're done here, we'll have built a polynomial that we will analyze further (in terms of g(x), c, and k) in the next section. For the following code segments below, count the operations and produce a corresponding polynomial representation. f(x) = public static boolean isEmpty() { return head == null: } f(x) = public static int num_occurrences (int n) { int count = 0: for(int i = 0: iExplanation / Answer
The number of abstract operations performed in the above code are:
1. 1(since the function isEmpty() has only one basic operation);
2.here inside the two for loops there is two basic operation and since both the for loops run for n times the number of times basic operation is executed is 2n^2.
3. here the function has one for loop which runs n times and it calls to numoccurences function. so the time complexity is n + 2n^2
4.here the for loop runs 2 to n times so the time complexity is nn-1.